The refractive index of a medium is $\sqrt{3}$. If unpolarised light is incident on it at the polarizing angle of the medium,then the angle of refraction is......$^o$

When unpolarized light is incident from air onto glass $(\mu = 1.5)$,then:

$A$ ray of light is incident at the polarising angle $\theta$ on an air-glass interface. If $\lambda_{a}$ and $\lambda_{g}$ are the wavelengths of light in air and glass respectively,then:

$A$ ray of light is incident at a polarising angle such that its deviation is $24^{\circ}$. Then the angle of incidence is: (in $^{\circ}$)

$A$ solid glass sphere of refractive index $n=\sqrt{3}$ and radius $R$ contains a spherical air cavity of radius $\frac{R}{2}$,as shown in the figure. $A$ very thin glass layer is present at the point $O$ so that the air cavity (refractive index $n=1$) remains inside the glass sphere. An unpolarized,unidirectional and monochromatic light source $S$ emits a light ray from a point inside the glass sphere towards the periphery of the glass sphere. If the light is reflected from the point $O$ and is fully polarized,then the angle of incidence at the inner surface of the glass sphere is $\theta$. The value of $\sin \theta$ is

The angle of polarisation for a medium is $60^o$. What will be the critical angle for this medium?